%lab5.m - solves the 4th order beam bending equation by the finite %difference method for steady-state and beam not touching the substrate %- fixed-fixed beam boundary conditions % For lab 5 in EE/ME 550 clear all %beam geometry Lb = 100; %um - beam length tb = 2; %um - beam thickness wb = 10; %um - beam width gap = 1; %um - gap under beam %beam properties sigma0 = 20; %MPa - residual stress in the film V = 100; %V %material properties E = 165e3; %MPa - Young's modulus nu = 0.2; %Poisson's ratio (unitless) %mesh properties N = 1000; %number of elements in the beam - must be at least four h = Lb/(2*N); %step size in x tol = 1e-6; %ratio of change in deflection to deflection magnitude %a few derived constants Epl = 1/(1/E - nu^2/E*(((wb/Lb))/(0.18 + (wb/Lb)))^(1.77*(Lb/tb)^-0.061)); %MPa - plate modulus I = wb*tb^3/12; %um^4 - moment of inertia Area = wb*tb; %um^2 - cross-sectional area rig = Epl*I; %uN*um^2 - beam flexural rigidity P = sigma0*(1-nu)*Area; %uN - force at the supports due to residual stress %analyze the beam %mesh the beam and initialize some variables wu = zeros(N+1,1); A = sparse(N,N); B = sparse(N,N); b = zeros(N,1); x = [0:h:Lb/2]'; fe = zeros(N,1); %calculate some constants which will be used in the equations c1 = h^4/rig; %um^2/uN g1 = -gap; %um c2 = P*h^2/rig; %unitless %set up the matrices A(1,1:3) = [7 -4 1]; B(1,1:2) = [-2 1]; A(2,1:4) = [-4 6 -4 1]; B(2,1:3) = [1 -2 1]; A(N-1,N-3:N) = [1 -4 7 -4]; B(N-1,N-2:N) = [1 -2 1]; A(N,N-2:N) = [2 -8 6]; B(N,N-1:N) = [2 -2]; for counter = 3:N-2 A(counter,counter-2:counter+2) = [1 -4 6 -4 1]; B(counter,counter-1:counter+1) = [1 -2 1]; end B = c2*B; %Now, we will iterate on the solution until the beam stops deflecting finished = 0; wlast = 2*wu+4; while finished==0 fe = electf(wu(2:N+1),gap,wb,V); bss = b + c1*fe; wu(2:N+1) = (A - B)\bss; if (max(abs(wu(2:N) - wlast(2:N))./abs(wu(2:N)))